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How to split then flatten with row number (index of the item flattened)?

Hi, I have a question regarding how to perform an operation in Denodo. I have data in a base view (on a Snowflake data source) that looks like: | Order_number | Icd10_codes | Icd9_codes | | -------- | -------- | -------- | | 1001 | 100.1,101.2 | | | 10...

flatten split row_number

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Split a column into different rows where value for the column is a list of strings.

There is a view a with one column value as ['avc','ghy']. How do I split these value in different rows? Output should be like avc ghy

Split

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how to parse out substring from a file-based data source

I have a data source that is based on a csv file. This file has a text column that can be pretty long and containg values that are structured as (AC12345) RANDOM TEXT Of VARYING LENGTH. The length of the string betwen the poarentheses are also varying,...

split file-based substring

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Split function in Denodo does not work! (second way) Regex for complex string in Denodo

I am basically trying to split the following string in Denodo and trying to create new columns in the database for each value. my_string = ABLMNC_154342_O_UW_UA-UCOU_SMC The problem i am facing is when i split the string, Denodo creates an arra...

Regex Split

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How to split a string at a delimiter

I have a string "India (IN)" I only want the country name India removing the delimiters and abbreviation (IN) Split function is not working.

Split

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Convert CSV into rows without the use of SPLIT function

Hi experts, Looking for alternative ways of converting comma separated values into rows without using the SPLIT/FLATTEN function as we want to delegate this completely to an oracle source. Please let me know if any ideas. Thanks.

Delegate FLATTEN Split